# How To Calculate Total Resistance In Parallel Circuit

By | October 19, 2022

Understanding how to calculate total resistance in a parallel circuit is essential for any electrical engineer. This can be daunting for someone with little knowledge of electricity, but it's actually quite simple when you break it down.

In electrical circuits, the resistance is the measure of how much force is needed to drive current through the circuit. In a parallel circuit, there are multiple resistors connected in parallel, so the current is divided among them. This allows the current to flow more freely than if all the components were connected in series.

To calculate the total resistance of a parallel circuit, you must first determine the individual resistance of each resistor. To do this, simply divide the voltage by the current in each resistor. Once you have the individual resistance for each resistor, add them up to get the total resistance.

Now that you know the total resistance of the circuit, you can calculate the total current flowing through the circuit. The total current is simply the sum of the individual currents going through each resistor. To calculate this, you need to multiply the voltage and the total resistance, then divide by the individual resistances.

The next step is to find the total power of the circuit. This can be done by multiplying the total current by the total voltage. This will give you the total power of the circuit.

Once you know this, you can use Ohm's Law to determine the amount of energy that is being used in the circuit. To do this, simply multiply the total power by the total resistance, then divide by the total voltage. This will give you the total energy used in the circuit.

Calculating the total resistance of a parallel circuit may seem like a complicated process, but with a little bit of practice, you'll be doing it with ease. Once you understand the principles of electricity and can calculate the individual resistance of each resistor, figuring out the total resistance of the circuit is fairly straightforward.

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